Question

What is the value of 3x^2+4y^2 if x=2,y=1 and z=-3

Answer 1

ANSWER

16

EXPLANATION

The given expression is;

$3 {x}^{2} + 4 {y}^{2}$

If x=2, y=1 and z=-3, we substitute the values into the expression and solve.

We substitute to obtain;

$3 {(2)}^{2} + 4 {(1)}^{2}$

We evaluate to get;

$3 {(4)} + 4 {(1)}$

We multiply out to get:

$12+ 4 = 16$

Therefore the value of the given expression is with the given values is 16