The cones are similar. Find the volume of cone B. Write your answer in terms of pi.
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Answer:
The volume of cone B is equal to [tex]256\pi\ ft^{3}[/tex]
Step-by-step explanation:
step 1
Find the scale factor
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
The scale factor is equal to the ratio of its diameters
so
16/8=2
step 2
Find the volume of cone B
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z -----> the scale factor
Vb ----> volume of cone B
Va ----> volume of cone a
[tex]z^{3}=\frac{Vb}{Va}[/tex]
we have
[tex]z=2[/tex]
[tex]Va=32\pi\ ft^{3}[/tex]
substitute
[tex]2^{3}=\frac{Vb}{32\pi}[/tex]
[tex]Vb=(8)(32\pi)=256\pi\ ft^{3}[/tex]
The volume of cone B that is similar to cone A is calculated as: 256π ft³.
Volume of Solid A/volume of solid B = a³/b³, where a and b are the corresponding linear measures of both solids.
32π/B = 4³/8³
B(4³) = (8³)(32π)
64(B) = 16,384π
B = 16,384π/64
Volume of cone B is: 256π ft³
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