Respuesta :

[tex]\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\ \cline{1-1} A=64\\ b=8 \end{cases}\implies 64=\cfrac{1}{2}(8)h\implies 64=4h \\\\\\ \cfrac{64}{4}=h\implies 16=h[/tex]

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