Question

A bag contains 5 red marbles, 6 white marbles, and 5 blue marbles. Find P(red and blue).

Please show work so I can undersand.

Answer 1

this is what you need to do in order to solve.

Answer 2

The probability of getting blue and red marble is $0.0976$.

What is Probability?

The probability of any event is the ratio of number of favourable outcome and Total number of outcome.

It is given that a bag contains $5$ red marbles, $6$ white marbles and $5$ blue marbles.

We have to find the Probability $\[\text{P}\left( \text{red and blue} \right)\]$.

So,

$\[\text{The total number of marbles in the bag}=5+6+5\]$

                                                              $= 16$

Probability of getting red marble $\[\text{P}\left( \text{red} \right)\text{=}\frac{\text{no}\text{.of red marbles}}{\text{total number of marbles}}$

                                                                   $\[=\frac{5}{16}\]$

Probability of getting white marble $\[\text{P}\left( \text{white} \right)\text{=}\frac{\text{no}\text{.of white marbles}}{\text{total number of marbles}}$

                                                                          $\[=\frac{6}{16}\]$

Probability of getting blue marble $\[\text{P}\left( \text{blue} \right)\text{=}\frac{\text{no}\text{.of blue marbles}}{\text{total number of marbles}}$

                                                                       $\[=\frac{5}{16}\]$

Now, we find the probability for $\[\text{P}\left( \text{red and blue} \right)\]$,

$\[\text{P}\left( \text{red and blue} \right)\] = \text{P}\left( \text{red} \right)\text{ }\!\!\times\!\!\text{ P}\left( \text{white} \right)$

$=\frac{5}{16}\cdot \frac{5}{16}$

$=0.0976$

Hence, the Probability of $\[\text{P}\left( \text{red and blue} \right)\]$ is $0.0976$.

Learn more about Probability:

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