Answer: [tex]1.38\frac{g}{cm^3}[/tex]
Step-by-step explanation:
You need to remember the formula for calculate the density:
[tex]density=\frac{mass}{volume}[/tex]
In this case:
[tex]density_{(rock)}=\frac{mass_{(rock)}}{Volume_{(rock)}}[/tex]
You know that:
[tex]mass_{(rock)}=15.5g[/tex]
And when it is placed in a graduated cylinder, the volume is displaced from 25.0 mL to 36.2 mL.
Then, the volume of the rock is:
[tex]Volume_{(rock)}=36.2mL-25.0mL=11.2mL[/tex]
Since [tex]1mL=1cm^3[/tex], you can rewrite the volume as:
[tex]Volume_{(rock)}=11.2cm^3[/tex]
Substituting values into the formula, you get that the density of the rock is:
[tex]density_{(rock)}=\frac{15.5g}{11.2cm^3}=1.38\frac{g}{cm^3}[/tex]
