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The number of chips of different colors in Amy's bag is shown below:


8 blue chips

9 pink chips

1 white chip

Amy takes out a chip from the bag randomly without looking. She replaces the chip and then takes out another chip from the bag. What is the probability that Amy takes out a pink chip in both draws?

9 over 18 multiplied by 8 over 17 equals 72 over 306

9 over 18 plus 8 over 17 equals 297 over 306

9 over 18 multiplied by 9 over 18 equals 81 over 324

9 over 18 plus 9 over 18 equals 18 over 18

Respuesta :

(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.

In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).

The total number of chips of different colors in Amy's bag is:

8 blue chips + 9 pink chips + 1 white chip = 18 color chips

Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.

So, the probability that Amy takes out a pink chip in the first draw is:

P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.

Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:

P(B) = 9/18  The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.

What is the probability that Amy takes out a pink chip in both draws?

P(A∩B) = P(A)P(B)

P(A∩B) = (9/18)(9/18) = 81/324

Probability of taking out pink chip in both draws is equal to [tex]9[/tex] over [tex]18[/tex]multiplied by [tex]9[/tex] over [tex]18[/tex] equals [tex]81[/tex] over [tex]324[/tex].

What is probability?

" Probability is defined as the ratio of number of favourable outcomes to the total number of outcomes."

Formula used

Probability [tex]= \frac{n(F)}{n(T)}[/tex]

[tex]n(F)=[/tex] Number of favourable outcomes

[tex]n(T)=[/tex] Total number of outcomes

For independent events

[tex]P(A\cap B) = P(A) \times P(B)[/tex]

According to the question,

Given,

Total number of chips [tex]= 18[/tex]

Number of pink chips [tex]= 9[/tex]

[tex]'A'[/tex] represents the event of taking out pink chip first time

[tex]'B'[/tex] represents the event of taking out pink chip second time

Probability of taking out pink chip first time [tex]'P(A)' = \frac{9}{18}[/tex]

After replaces the chips again number of chip remain same

Probability of taking out pink chip second time [tex]'P(B)' = \frac{9}{18}[/tex]

Both the events are independent to each other

Substitute the value in the formula of probability of independent event we get,

Probability of taking out pink chip in both draw

[tex]P(A \cap B) = \frac{9}{18} \times \frac{9}{18}[/tex]

               [tex]= \frac{81}{324}[/tex]

Hence, probability of taking out pink chip in both draw is equal to [tex]9[/tex] over [tex]18[/tex]multiplied by [tex]9[/tex] over [tex]18[/tex] equals [tex]81[/tex] over [tex]324[/tex].

Learn more about probability here

brainly.com/question/11234923

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