Answer:
[tex]-\frac{7}{3}[/tex]
Step-by-step explanation:
To solve this, we are using the average rate of change formula:
[tex]m=\frac{f(b)-f(a)}{b-a}[/tex]
where
[tex]m[/tex] is the average rate of change
[tex]a[/tex] is the first point
[tex]b[/tex] is the second point
[tex]f(a)[/tex] is the function evaluated at the first point
[tex]f(b)[/tex] is the function evaluated at the second point
We want to know the average rate of change of the function [tex]f(x)=0.5^x-6[/tex] form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, [tex]a=-3[/tex] and [tex]b=0[/tex].
Replacing values
[tex]m=\frac{f(b)-f(a)}{b-a}[/tex]
[tex]m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}[/tex]
[tex]m=\frac{1-6-(8-6)}{3}[/tex]
[tex]m=\frac{-5-(2)}{3}[/tex]
[tex]m=\frac{-5-2}{3}[/tex]
[tex]m=\frac{-7}{3}[/tex]
[tex]m=-\frac{7}{3}[/tex]
We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is [tex]-\frac{7}{3}[/tex]