Find the value of x. Round to the nearest tenth.
Please help me!!

Answer:
x ≈ 4.4 in
Step-by-step explanation:
The segment from the centre to the chord is a perpendicular bisector.
The third side of the right triangle = 7.4 ÷ 2 = 3.7
Consider the right triangle with legs 3.7 and 2.4 and hypotenuse x
Using Pythagoras' identity
x² = 2.4² + 3.7² = 5.76 + 13.69 = 19.45
Take the square root of both sides
x = [tex]\sqrt{19.45}[/tex] ≈ 4.4