Question

the volume of a sphere is 2,098 pi m^3 what is the surface area of the sphere to the nearest tenth?
1700
146.2
850
26,364

Answer 1

Answer:

3139.5 m²

Step-by-step explanation:

the formula for the volume of a sphere of radius r is V = (4/3)πr³.  In this particular case, V = 2098π m³ = (4/3)πr³, and from this we can calculate the radius, r:

       2098π m³

r³ = -----------------  =  (3/4)(2098 = 1483/5

       (4/3)π

Thus r = ∛1573.5 m³ =  11.64 m

Then the surface area is A = 4πr², which in this case is

A = 4(3.14159)(11.64 m)^2 = 1702.6 m² (which is to the nearest tenth).

Answer 2

The surface of the sphere whose Volume is 2098 π is 1701.7  $m^{2}$

What is Surface Area?

Surface area is the amount of space covering the outside of a three-dimensional shape.

It is given that:

Volume of sphere= $\frac{4}{3}$ * π *$r^{3}$

2098  π = $\frac{4}{3}$ * π *$r^{3}$

2098 = $\frac{4}{3}$ *$r^{3}$

$r^{3}$= $\frac{2098*3}{4}$

$r^{3}$= 1573.5

r= 11.64

Surface Area of sphere= 4 π$r^{2}$

                                      = 4* 3.14 *11.64 * 11.64

                                      = 1701.749376 $m^{2}$

                                      = 1701.7  $m^{2}$

Hence the surface area of the sphere is 1701.7  $m^{2}$.

Learn more about Surface Area here:

https://brainly.com/question/14692728

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