Find the value of x. Round to the nearest tenth. Please Help Me!!!

Answer:
x ≈ 4.1 cm
Step-by-step explanation:
The segment from the centre to the chord is a perpendicular bisector
The third side of the triangle = 14.6 ÷ 2 = 7.8
We now have a right triangle with legs x and 7.8 with hypotenuse 8.8
Using Pythagoras' identity on the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 7.8² = 8.8²
x² + 60.84 = 77.44 ( subtract 60.84 from both sides )
x² = 16.6 ( take the square root of both sides )
x = [tex]\sqrt{16.6}[/tex] ≈ 4.1 ( nearest tenth )
Answer:
4.1
Step-by-step explanation:
⇒The missing side of the triangle is 7.8 cm
We use Pythagoras theorem to solve x
a² = b² + c²
In this case, a = 7.8 cm and c = 8.8 cm
→ 7.8² = x² + 8.8²
( Rearrange )
→ x² = 8.8² - 7.8²
( Simplify )
→ x² = 77.44 - 60.84
( Simplify )
→ x² = 16.6
( Square root )
→ x = 4.074309757