Based on the free-body diagram, the net force acting on this firework is 0 Newton.
What is Newton's second law?
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = m*a
where F represents the force applied
m is the mass of the object
a is the acceleration of the object
By using the equilibrium of the forces
The net horizontal forces acting on the firework should be zero.
as well the net vertical forces acting on the firework should be zero.
As there is no horizontal force acting on the rocket then the net horizontal force is already zero and has no significance in this problem.
Fh=0
For balancing the vertical force, the net vertical force on the firework is zero as both the upward force and downward force are equal in magnitude but opposite in direction.
Net vertical force= Net upward force - net downward force
= 9452-9452
=0 N
Thus, we can conclude on the basis of the free-body diagram, that the net force acting on this firework is 0 Newton.
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