The probability of a student getting an A....

Answer:
[tex]P (M\ and\ C) = \frac{1}{4}=25\%[/tex]
Step-by-step explanation:
We call M the event in which a student gets an A in math and we call C the event in which a student gets an A in chemistry. As the events are not mutually exclusive, then.
[tex]P (M\ or\ C) = P (M) + P (C) - P (M\ and\ C)[/tex]
In this case we know that:
[tex]P (M\ or\ C) = \frac{7}{10}[/tex]
[tex]P (M) =\frac{17}{20}[/tex]
[tex]P (C) =\frac{1}{10}[/tex]
So
[tex]P (M\ and\ C) = P (M) + P (C) - P (M\ or\ C)[/tex]
[tex]P (M\ and\ C) = \frac{17}{20} + \frac{1}{10} -\frac{7}{10}[/tex]
[tex]P (M\ and\ C) = \frac{1}{4}[/tex]