Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost
$1.30 per pound, and a pumpkin costs $5.20
The inequality 1.30x + 5.20 18.20 models this situation, where x is the
number of pounds of oranges.
Solve the inequality. How many pounds of oranges can Antoine buy?

Respuesta :

Answer:

10 pounds

Step-by-step explanation:

You forgot the inequality sing, but since Antoine can't spend more than $18.20, I am positive that the sign is [tex]\leq[/tex] (Antony can spend $18.20 or less than $18.20).

Therefore, our inequality is: [tex]1.30x+5.20\leq 18.20[/tex]

where [tex]x[/tex] is the pounds of oranges

Let's solve step-by-step to find how many pounds of oranges he can buy

Step 1. Subtract 5.20 fro both sides of the inequality

[tex]1.30x+5.20-5.20\leq 18.20-5.20[/tex]

[tex]1.30x\leq 13[/tex]

Step 2. Divide both sides of the inequality by 1.30

[tex]\frac{1.30x}{1.30} \leq \frac{13}{1.30}[/tex]

[tex]x\leq 10[/tex]

We can conclude that Antony can buy 10 pounds of oranges.

ACCESS MORE
EDU ACCESS