Respuesta :
For this case we have the following function:
[tex]c (f) = \frac {5} {9} (f-32)[/tex]
We must find the inverse function. For this we follow the steps below:
Replace c (f) with y:
[tex]y = \frac {5} {9} (f-32)[/tex]
We exchange variables:
[tex]\frac {5} {9} (y-32) = f[/tex]f = \frac {5} {9} (y-32)
We solve for "y":
[tex]\frac {5} {9} (y-32) = f[/tex]
We multiply by[tex]\frac {9} {5}[/tex]on both sides of the equation:
[tex]y-32 = \frac {9} {5} f[/tex]
We add 32 to both sides of the equation:
[tex]y = \frac {9} {5} f + 32[/tex]
We change y by[tex]c^{ -1} (f):[/tex]
[tex]c^{-1} (f) = \frac {9} {5} f + 32[/tex]
Answer:
[tex]c^{-1} (f) = \frac {9} {5} f + 32[/tex]
Answer:
[tex]f(c)=\frac{9}{5}c+32[/tex]
Step-by-step explanation:
Given function that is used to convert degrees to Fahrenheit to degrees Celsius,
[tex]c(f)=\frac{5}{9}(f-32)[/tex]
Let y represents the output value of the function and x represents the input value,
[tex]y=\frac{5}{9}(x-32)[/tex]
Switch x and y,
[tex]x=\frac{5}{9}(y-32)[/tex]
Isolate y,
[tex]9x=5(y-32)[/tex]
[tex]\frac{9}{5}x=y-32[/tex]
[tex]\implies y = \frac{9}{5}x+32[/tex]
[tex]\implies f(c)=\frac{9}{5}c+32[/tex]
Which is the required function.