Question

What are the center and radius of the circle with equation (x-7)^2 + (y+5)^2 = 36?

Answer 1

Answer:

Center (7, -5) and radius=6

Step-by-step explanation:

The question is on center and radius of a circle

The general circle equation is given as (x-h)² + (y-k)²= r² where the center is (h,k) and radius is r

Given   (x-7)^2 + (y+5)^2 = 36?

           

            (x-7)²  + (y+5)²= 6²

     

h=7 and y=-5 and r=6

Answer 2

ANSWER

Center:(7,-5)

Radius:r=6

EXPLANATION

The given circle has equation;

${(x - 7)}^{2} + {(y + 5)}^{2} = 36$

We can rewrite this as:

${(x - 7)}^{2} + {(y - - 5)}^{2} = {6}^{2}$

Comparing this to the standard equation of the circle:

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

we have h=7,k=-5, and r=6.

Therefore the center (h,k)=(7,-5) and the radius is r=6.