Answer:
10th term of the sequence 64,16,4... = 1/4096
Step-by-step explanation:
Points to remember
nth term of GP is given by.
Tₙ = ar⁽ⁿ⁻¹⁾
Where r is the common ratio and a is the first term
To find the 10th term of given GP
It is given that,
64, 16, 4,......
a = 64 and 6 = 1/4 Here
T₁₀ = ar⁽ⁿ⁻¹⁾
= 64 * (1/4)⁽¹⁰⁻¹⁾ = 64 * (1/4⁹)
= 4³/4⁹ = 1/4⁶ = 1/4096
