Right triangle ABC is shown
Which equation can be used to solve for c?
3 m
sin(509) = 3
O sin(509=
O cos(50°) =
cos(509)=

Right triangle ABC is shown Which equation can be used to solve for c 3 m sin509 3 O sin509 O cos50 cos509 class=

Respuesta :

Answer:

[tex]\sin (50\degree)=\frac{3}{c}[/tex]

Step-by-step explanation:

The given triangle is a right triangle with a given angle which is [tex]50\degree[/tex].

The side opposite to the 50 degree angle is 3 meters.

The hypotenuse is 'c' units.

We can use the sine ratio to obtain:

[tex]\sin (50\degree)=\frac{opposite}{hypotenuse}[/tex]

[tex]\sin (50\degree)=\frac{3}{c}[/tex]

Therefore the correct answer is A.

The required equation can be used to solve for c is sin 50 = 3/c

SOH CAH TOA identity

From the figure shown, the measured sides are:

  • Opposite = 3m
  • Hypotenuse  = c
  • m<B = 50 degrees

USing the SOH CAH TOA identity

sin theta = opp/hyp

sin 50 = 3/c

Hence the required equation can be used to solve for c is sin 50 = 3/c

Learn more on SOH CAH TOA here: https://brainly.com/question/20734777

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