The area is 64. Area, as you probably know, is the length times the width of the figure. The length from A to C is approximately radical 128, and the length from C to D is approximately radical 32 (btw, the radical is the check mark with line that goes above and next to the radicand (the number on the inside of the radical)). Multiply these two to get the area, and you should end up with 64.
If the quadrilateral has vertices at (-8, 0), (-4,-4), (0,8), and (4,4). Then the area of the quadrilateral will be 64 square units.
It is a polygon with four sides. The total interior angle is 360 degrees.
The quadrilateral shown below has vertices at (-8, 0), (-4,-4), (0,8), and (4,4).
Then the area of the quadrilateral will be
Assume the points
(x₁, y₁) = (-8, 0)
(x₂, y₂) = (-4, -4)
(x₃, y₃) = (4, 4)
(x₄, y₄) = (0, 8)
Then the area of the quadrilateral is given as
Area = 1/2 |[(x₁y₂ + x₂y₃ + x₃y₄ + x₄y₁) - (y₁x₂ + y₂x₃ + y₃x₄ + y₄x₁)]|
Area = 1/2|[(-8 × -4 + -4×4 + 4×8 + 0×0) - (0 × -4 + -4 × 4 + 4 × 0 + 8 × -8)]|
Area = 1/2|[(32 - 16 + 32) - ( -16 - 64)]|
Area = 1/2|[48 + 80]|
Area = 1/2|128|
Area = 64
More about the quadrilateral link is given below.
https://brainly.com/question/13805601
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