Find the value of the indicated angles. 8 is incorrect! I'm so confused.. SHOW YOUR WORK!!

The inscribed angle theorem tells you that both angles must have the same measure, so
[tex]2(3m+2)=4m+20[/tex]
[tex]6m+4=4m+20[/tex]
[tex]2m=16[/tex]
[tex]m=8[/tex]
But this isn't the final answer! You're supposed to find the angles' measures, which are [tex]2(3m+2)^\circ[/tex] and [tex](4m+20)^\circ[/tex] where [tex]m=8[/tex]. So the answer is [tex]2(3\cdot8+2)^\circ=\boxed{52^\circ}[/tex].
The inscribed angle is half that of the arc it comprises. The measure of both the angle is 52°.
we know that the inscribed angle is half that of the arc it comprises.
Here, the arc that the inscribed angles comprise is the same.
2(3m+2)° = (4m+20)°
by solving for m
6m + 4 = 4m + 20
6m - 4m = 20 - 4
2m = 16
m = 8
To find the measure of the angle
(4m+20)°= 4(8) + 20 = 52°
2(3m+2)° = 2(26) = 52
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