Respuesta :

The inscribed angle theorem tells you that both angles must have the same measure, so

[tex]2(3m+2)=4m+20[/tex]

[tex]6m+4=4m+20[/tex]

[tex]2m=16[/tex]

[tex]m=8[/tex]

But this isn't the final answer! You're supposed to find the angles' measures, which are [tex]2(3m+2)^\circ[/tex] and [tex](4m+20)^\circ[/tex] where [tex]m=8[/tex]. So the answer is [tex]2(3\cdot8+2)^\circ=\boxed{52^\circ}[/tex].

The inscribed angle is half that of the arc it comprises. The measure of both the angle is 52°.

How do we relate the inscribed angle and the arc?

we know that the inscribed angle is half that of the arc it comprises.

Here, the arc that the inscribed angles comprise is the same.

2(3m+2)° = (4m+20)°

by solving for m

6m + 4 = 4m + 20

6m - 4m = 20 - 4

2m = 16

m = 8

To find the measure of the angle

(4m+20)°= 4(8) + 20 = 52°

2(3m+2)° = 2(26) = 52

Learn more about angles here:

https://brainly.com/question/27458498

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