Question

Write probability in a fraction

Answer 1

Answer:

$P (even,\ then\ not\ 2) = \frac{5}{12}$

Step-by-step explanation:

When launching a numerical cube there are 6 possible results

S = {1, 2, 3, 4, 5, 6}

Among these possible outcomes only 3 are even numbers

S = {2, 4, 6}

So the probability of obtaining an even number is

$P = \frac{3}{6}\\\\P = \frac{1}{2}$

Then, the probability of obtaining a number other than 2 is:

$P = \frac{5}{6}$.

If 2 launches are made then the events are independent,

Thus:

P(even, then not 2) is

$P (even,\ then\ not\ 2) = \frac{1}{2} * \frac{5}{6}\\\\P (even,\ then\ not\ 2) = \frac{5}{12}$