Question

Please Help Quickly!!!

Find the slope of the tangent line of each equation at x = 1.

y = x^2

Answer 1

It's the value of $\dfrac{\mathrm dy}{\mathrm dx}$ when $x=1$:

$y=x^2\implies\dfrac{\mathrm dy}{\mathrm dx}=2x$

When $x=1$, the derivative/slope is 2, so the answer is C.