Answer:
6 m/s^2
Explanation:
The average acceleration of the car is given by:
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final speed
u is the initial speed
t is the time elapsed
For the car in this problem,
v = 22 m/s
u = 4 m/s
t = 3 s
Therefore, the acceleration of the car is
[tex]a=\frac{22 m/s-4 m/s}{3 s}=6 m/s^2[/tex]