A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4m/s. But 3 seconds later at the bottom of the slope its speed is 22m/s. What is its average acceleration?

Respuesta :

Answer:

6 m/s^2

Explanation:

The average acceleration of the car is given by:

[tex]a=\frac{v-u}{t}[/tex]

where

v is the final speed

u is the initial speed

t is the time elapsed

For the car in this problem,

v = 22 m/s

u = 4 m/s

t = 3 s

Therefore, the acceleration of the car is

[tex]a=\frac{22 m/s-4 m/s}{3 s}=6 m/s^2[/tex]

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