Respuesta :
Answer:
[tex]\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}[/tex]
Explanation:
At the beginning, you have two reactions happening:
[tex]\rm HCl + H$_{2}$O$ $\, \longrightarrow \,$ H$_{3}$O$^{+}$ + Cl$^{-}$\\\rm HClO$_{2}$ + H$_{2}$O$ $\, \rightleftharpoons \,$ H$_{3}$O$^{+}$ + ClO$_{2}^{-}$[/tex]
As you add KOH(aq), it does two things:
- It increases the volume of the solution.
- It reacts with the hydronium ions to form water.
A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.
B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.
C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.
D) As HClO₂ reacts, it forms ClO₂⁻. [tex]\boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}[/tex]
The amount of ClO2- increases as aqueous KOH is added.
Acids
- Acids are substances which donate hydrogen ions or protons in aqueous solutions.
- Acids can either be strong or weak.
Strong acids ionize completely in solution to produce hydrogen ions.
Weak acids only ionize partially in solution to produce hydrogen ions.
- HCl is a strong acid and ionizes completely to produce hydrogen and chloride ions.
- HClO2 is a weak acid and only ionizes partially.
When aqueous KOH is added to a mixture of HCl and HClO2, the follow occurs:
- Hydrogen ions from HCl are removed, hence H+ reduces.
- Cl- amount remains the same but is diluted as the volume of solution increases.
- ClO2- increases as the hydrogen ions are removed from the partially ionized HClO2.
- HClO2 decreases due to equilibrium shift towards formation of more H+ and ClO2-
Therefore, the amount of ClO2- increases as aqueous KOH is added.
Learn more about weak and strong acid at: https://brainly.com/question/15192126