Question

polygon A i simllar to polgon B. find the perimeer of polygon B if one side of polygon A is 24 A sde to polygon B is 15 and the perimeter of polgon A is 128

Answer 1

Answer:

Perimeter of polygon B = 80 units

Step-by-step explanation:

Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

Let $x$ be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.

Let's replace those value sin our proportion and solve for $x$:

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

$\frac{24}{15} =\frac{128}{x}$

$x=\frac{128*15}{24}$

$x=\frac{1920}{24}$

$x=80$

We can conclude that the perimeter of polygon B is 80 units.

Answer 2

Answer:80 units

Step-by-step explanation:

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