Respuesta :
Answer:
Perimeter of polygon B = 80 units
Step-by-step explanation:
Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.
[tex]\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}[/tex]
Let [tex]x[/tex] be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.
Let's replace those value sin our proportion and solve for [tex]x[/tex]:
[tex]\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}[/tex]
[tex]\frac{24}{15} =\frac{128}{x}[/tex]
[tex]x=\frac{128*15}{24}[/tex]
[tex]x=\frac{1920}{24}[/tex]
[tex]x=80[/tex]
We can conclude that the perimeter of polygon B is 80 units.
Answer:80 units
Step-by-step explanation:
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