Answer:
0.9 J/g.°C.
Explanation:
- To solve this problem, we can use the relation:
Q = m.c.ΔT,
where, Q is the amount of energy (Q = 132.8 J).
m is the mass of Al (m = 11.17 g).
c is the specific heat capacity of Al (c of Al = ??? J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 28.94°C - 15.73°C = 13.21°C).
∵ Q = m.c.ΔT
∴ (132.8 J) = (11.17 g)(c)(13.21°C).
∴ c = (132.8 J)/(11.17 g)(13.21°C) = 0.9 J/g.°C.
