Question

Can anybody please help me ?


1 The average salary for a professional baseball player in the United States can be approximated by = 283(1.2)^t where t=0 represents the year 1984. Using this approximation, find the ratio of an average salary in 1988 to the average salary in 1994.


2 Find and correct the error(s) in the problem below. Explain your correction(s).


x^-9/x^-3=x^-9-3

=x^-12

=1/x^-12

Answer 1

Here the answer is in this picture

Answer 2

Answer:

1. Ratio is 1 : 3

Step-by-step explanation:

1. The average salary for a professional baseball player in the United States can be approximated by = $283(1.2)^{t}$

Where t = 0 represents the year 1984.

Salary in year 1988 = $283(1.2)^{4}$  [t = 4 years]

Salary in year 1994 = $283(1.2)^{10}$ [t = 10 years]

Ratio of the average salary in 1988 to the average salary in 1994 = $\frac{283(1.2)^{4}}{283(1.2)^{10}}=\frac{(1.2)^{4}}{(1.2)^{10}}$

= $\frac{1}{(1.2)^{10-4}}=\frac{1}{(1.2)^{6}}$

= $\frac{1}{3}$

2. Corrected form

$\frac{x^{-9} }{x^{-3}}$

= $x^{-9+3}$[since $\frac{a^{1}}{a^{1}}=a^{1-1}=a^{0}=1$]

= $x^{-6}$

= $\frac{1}{x^{6}}$  [ since $\frac{1}{a^{1}}=a^{-1}$ ]

Now we can compare the corrections and errors in the highlighted form.

Expression needs correction

$\frac{x^{-9} }{x^{-3}}$

= $x^{-9-3}$

=  $x^{-12}$

= $\frac{1}{x^{-12}}$