Respuesta :
Answer:
Minimum Unit Cost = $14,362
Step-by-step explanation:
The standard form of a quadratic is given by:
ax^2 + bx + c
So for our function, we can say,
a = 0.6
b = -108
c = 19,222
We can find the vertex (x-coordinate where minimum value occurs) by the formula -b/2a
So,
-(-108)/2(0.6) = 108/1.2 = 90
Plugging this value into original function would give us the minimum (unit cost):
[tex]c(x)=0.6x^2-108x+19,222\\c(90)=0.6(90)^2-108(90)+19,222\\=14,362[/tex]
Answer:
The minimum unit cost is 14,362
Step-by-step explanation:
The minimum unit cost is given by a quadratic equation. Therefore the minimum value is at its vertex
For a quadratic function of the form
[tex]ax ^ 2 + bx + c[/tex]
the x coordinate of the vertex is
[tex]x=-\frac{b}{2a}[/tex]
In this case the equation is: [tex]c(x) = 0.6x^2-108x+19,222[/tex]
Then
[tex]a= 0.6\\b=-108\\c=19,222[/tex]
Therefore the x coordinate of the vertex is:
[tex]x=-\frac{(-108)}{2(0.6)}[/tex]
[tex]x=90[/tex]
Finally the minimum unit cost is:
[tex]c(90)=0.6(90)^2-108(90)+19,222\\\\c(90)=14,362[/tex]