Answer:
The combinations are
1. [tex]2\times 10^{-4}[/tex] C , [tex]15\times 10^{-4}[/tex]
2. [tex]3\times 10^{-4}[/tex] C , [tex]10\times 10^{-4}[/tex]
Explanation:
The force between two charges q and Q is given by Coulomb's law.
The coulomb force is given by
[tex]F = \frac{1}{4\prod \varepsilon _{0}}\times \frac{Q\times q}{r^{2}}[/tex]
Where, r be the distance between two charges
According to the question,
r = 15 cm, Q = [tex]6\times 10^{-4}[/tex] C, q = [tex]5\times 10^{-4}[/tex] C , F = 12 N
Force remains same, distance remains same
so the product of Q and q be same
The product of Q and q is [tex]30\times 10^{-8}[/tex]
So other combination of charges are
1. [tex]2\times 10^{-4}[/tex] C , [tex]15\times 10^{-4}[/tex]
2. [tex]3\times 10^{-4}[/tex] C , [tex]10\times 10^{-4}[/tex]
