Answer:
see explanation
Step-by-step explanation:
A
If the sequence is arithmetic then the common difference d is
d = t - 4 = 9 -t, that is
t - 4 = 9 - t ( add t to both sides )
2t - 4 = 9 ( add 4 to both sides )
2t = 13 ( divide both sides by 2 )
t = [tex]\frac{13}{2}[/tex] = 6 [tex]\frac{1}{2}[/tex]
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B
If the sequence is geometric then the common ratio r is
r = [tex]\frac{t}{4}[/tex] = [tex]\frac{9}{t}[/tex] ( cross- multiply )
t² = 36 ( take the square root of both sides )
t = [tex]\sqrt{36}[/tex] = 6
A: If the sequence is arithmetic, what is the value of t is 6.5.
B: If the sequence is geometric, what is the value of t is 6.
If the sequence is arithmetic then the common difference d is,
An arithmetic sequence is a sequence of numbers where the differences between every two consecutive terms are the same.
d = t - 4
d= 9 -t,
that is,
t - 4 = 9 - t ( add t to both sides )
2t - 4 = 9 ( add 4 to both sides )
2t = 13 ( divide both sides by 2 )
t =[tex]\frac{13}{2}[/tex] = 6.5
If the sequence is geometric then the common ratio r is
r = [tex]\frac{t}{4} =\frac{9}{t}[/tex] = ( cross- multiply )
t² = 36 ( take the square root of both sides )
t = [tex]\sqrt{36}[/tex]= 6
Therefore we get,
A: If the sequence is arithmetic, what is the value of t is 6.5.
B: If the sequence is geometric, what is the value of t is 6
To learn more about the sequence visit:
https://brainly.com/question/6561461
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