Answer:
B. [tex]f^{-1} (x)=\sqrt[3]{x} +2[/tex]
Step-by-step explanation:
We are given the function [tex]f(x)=x^3-6x^2+12x-8[/tex]
In order to find the inverse, we will need to swap f(x) for y. And then we will switch the locations of x and y. Then we will solve for y.
[tex]f(x)=x^3-6x^2+12x-8\\\\y=x^3-6x^2+12x-8\\\\x=y^3-6y^2+12y-8\\\\x=(y-2)^3\\\\\sqrt[3]{x} =y-2\\y=\sqrt[3]{x} +2\\\\f^{-1} (x)=\sqrt[3]{x} +2[/tex]
