Question

5y(2x-1)=y(x+2)+20, x=3​

Answer 1

Answer:

y=1

Step-by-step explanation:

5y(2x-1)=y(x+2)+20, x=3

5y(2(3)-1)=y(3+2)+20

5y(6-1)=y(5)+20

5y(5)=5y+20

25y=5y+20

25y-5y=20

20y=20

y=20/20

y=1

Answer 2

5y(2x-1)=y(x+2)+20, x=3​

Step 1: Substitute x with 3

5y(2(3) - 1) = y(3 + 2) + 20

Step 2: Combine like terms in the parentheses

5y(6 - 1) = y(3 + 2) + 20

5y(5) = y(3 + 2) + 20

5y(5) = y(5) + 20

Step 2: Distribute the number outside the parentheses to the numbers inside the parentheses

25y  = 5y + 20

Step 3: Combine like terms by subtracting 5y to both sides

25y-5y  = (5y-5y) + 20

20y = 20

Step 4: Divide 20 to both sides to isolate y

$\frac{20y}{20} = \frac{20}{20}$

y = 1

Check:

5(1) (2(3) - 1) = 1(3+2) + 20

5(6-1) = 1(5) + 20

5(5) = 5 + 20

25 = 25

Hope this helped!