Question

simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)

Answer 1

Answer:

The simplest form is x/(x + 3)

Step-by-step explanation:

* To simplify the rational Expression lets revise the factorization

  of the quadratic expression

*  To factor a quadratic in the form x² ± bx ± c:

- First look at the c term  

# If the c term is a positive number, and its factors are r and s they

  will have the same sign and their sum is b.

#  If the c term is a negative number, then either r or s will be negative

   but not both and their difference is b.

- Second look at the b term.  

# If the c term is positive and the b term is positive, then both r and

  s are positive.  

Ex: x² + 5x + 6 = (x + 3)(x + 2)  

# If the c term is positive and the b term is negative, then both r and s

  are negative.  

Ex:  x² - 5x + 6 = (x -3)(x - 2)

# If the c term is negative and the b term is positive, then the factor

  that is positive will have the greater absolute value. That is, if

  |r| > |s|, then r is positive and s is negative.  

Ex: x² + 5x - 6 = (x + 6)(x - 1)

# If the c term is negative and the b term is negative, then the factor

  that is negative will have the greater absolute value. That is, if

  |r| > |s|, then r is negative and s is positive.

Ex: x² - 5x - 6 = (x - 6)(x + 1)

* Now lets solve the problem

- We have two fractions over each other

- Lets simplify the numerator

∵ The numerator is $\frac{x+2}{x^{2}+2x-3}$

- Factorize its denominator

∵  The denominator = x² + 2x - 3

- The last term is negative then the two brackets have different signs

∵ 3 = 3 × 1

∵ 3 - 1 = 2

∵ The middle term is +ve

∴ -3 = 3 × -1 ⇒ the greatest is +ve

∴ x² + 2x - 3 = (x + 3)(x - 1)

∴ The numerator = $\frac{(x+2)}{(x+3)(x-2)}$

- Lets simplify the denominator

∵ The denominator is $\frac{x+2}{x^{2}-x}$

- Factorize its denominator

∵  The denominator = x² - 2x

- Take x as a common factor and divide each term by x

∵ x² ÷ x = x

∵ -x ÷ x = -1

∴ x² - 2x = x(x - 1)

∴ The denominator = $\frac{(x+2)}{x(x-1)}$

* Now lets write the fraction as a division

∴ The fraction = $\frac{x+2}{(x+3)(x-1)}$ ÷ $\frac{x+2}{x(x-1)}$

- Change the sign of division and reverse the fraction after it

∴ The fraction = $\frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}$

* Now we can cancel the bracket (x + 2) up with same bracket down

 and cancel bracket (x - 1) up with same bracket down

∴ The simplest form = $\frac{x}{x+3}$

Answer 2

ANSWER

$\frac{x}{x + 3}$

EXPLANATION

We want to simplify:

$\frac{x +2 }{ {x}^{2} + 2x - 3} \div \frac{x + 2}{ {x}^{2}- x}$

Multiply by the reciprocal of the second fraction:

$\frac{x +2 }{ {x}^{2} + 2x - 3} \times \frac{{x}^{2}- x}{ x + 2}$

Factor;

$\frac{x +2 }{ (x + 3)(x - 1)} \times \frac{x(x - 1)}{ x + 2}$

We cancel out the common factors to get:

$\frac{x}{x + 3}$