Respuesta :

ANSWER

[tex] \sum _{n = 1} ^{6} 2n[/tex]

EXPLANATION

The series is:

2 + 4 + 6 + 8 + 10 + 12

The first term is:

f(1)=2

The common difference is

[tex]d= 4 - 2 = 2[/tex]

The formula for the corresponding sequence is

[tex]f(n) = 2 + 2(n - 1)[/tex]

[tex]f(n) = 2 + 2n - 2[/tex]

[tex]f(n) = 2n[/tex]

The summation notation is:

[tex] \sum _{n = 1} ^{6} 2n[/tex]