Answer: OPTION A.
Step-by-step explanation:
You can observe that in the figure CDEF the vertices are:
[tex]C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)[/tex]
And in the figure C'D'E'F' the vertices are:
[tex]C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)[/tex]
For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:
For C'(-8,-4) and C(-2,-1):
[tex]\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4[/tex]
Let's choose another vertex. For E'(8,8) and E(2,2):
[tex]\frac{8}{2}=4\\\\\frac{8}{2}=4[/tex]
You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.
Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:
[tex](x, y)[/tex]→[tex](4x, 4y)[/tex]