Question

The equation of trajectory of a projectile is y=10x-(5/9)x^2 if we assume g=10m/s^2, the range of projectile in meters is?

Answer 1

Answer:

18 m

Explanation:

y = 10x − 5/9 x²

When the projectile lands, y=0:

0 = 10x − 5/9 x²

0 = x (10 − 5/9 x)

x = 0, 18

The range of the projectile is 18 m.