Solve for X
A: 12.5
B: 5
C: 6[tex]\sqrt{3}[/tex]
D:12
![Solve for X A 125 B 5 C 6texsqrt3tex D12 class=](https://us-static.z-dn.net/files/d36/93c3b2e6245f8676380f5368e71f8706.png)
Answer:
Step-by-step explanation:
(LOOK AT THE PICTURE)
ΔADC and ΔCDB are similar (AAA). Therefore the corresponding sides are in proportion:
[tex]\dfrac{AD}{CD}=\dfrac{CD}{DB}[/tex]
We have
[tex]AD=16,\ CD=x,\ DB=9[/tex]
Substitute:
[tex]\dfrac{16}{x}=\dfrac{x}{9}[/tex] cross multiply
[tex]x^2=(9)(16)\to x=\sqrt{(9)(16)}\\\\x=(\sqrt9)(\sqrt{16})\\\\x=(3)(4)\\\\x=12[/tex]
bear in mind that, a perpendicular line stemming from the right-angle like so, creates three similar triangles, a large one, containing the other two smaller ones, a medium and a small.
so.. .we can just use the medium and small proportions.
Check the picture below.