Respuesta :

gmany

Answer:

D. 12

Step-by-step explanation:

(LOOK AT THE PICTURE)

ΔADC and ΔCDB are similar (AAA). Therefore the corresponding sides are in proportion:

[tex]\dfrac{AD}{CD}=\dfrac{CD}{DB}[/tex]

We have

[tex]AD=16,\ CD=x,\ DB=9[/tex]

Substitute:

[tex]\dfrac{16}{x}=\dfrac{x}{9}[/tex]          cross multiply

[tex]x^2=(9)(16)\to x=\sqrt{(9)(16)}\\\\x=(\sqrt9)(\sqrt{16})\\\\x=(3)(4)\\\\x=12[/tex]

Ver imagen gmany

bear in mind that, a perpendicular line stemming from the right-angle like so, creates three similar triangles, a large one, containing the other two smaller ones, a medium and a small.

so.. .we can just use the medium and small proportions.

Check the picture below.

Ver imagen jdoe0001
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