Question

Two cars started moving in opposite directions from the same point at the same moment of time. If the speed of one car is 50 mph, and the other car goes at a speed of 60 mph, how soon the distance between them will become 1320 miles?

Answer 1

<---------------------------||----------------------------------------->

           A                                         B

          50 mph                               60 mph

so let's recall that d = rt, distance = rate * time.

both cars start out at the same time, say "t" hours.

after "t" hours car A has covered say "d" miles, since there's a total of 1320, then car B must surely had covered the slack, or 1320 - d.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ A&d&50&t\\ B&1320-d&60&t \end{array}\qquad \implies \begin{cases} ~\hfill \boxed{d}=50t\\ 1320-d=60t \end{cases} \\\\\\ 1320-\boxed{50t}=60t\implies 1320=110t\implies \cfrac{1320}{110}=t\implies 12=t$

Answer 2

Answer:

To cover 1320 miles they will need 12 hours of time.

Step-by-step explanation:

Given information:

The cars are moving in opposite direction and the starting point of the cars are same:

The speed of first car $=50 mph$

The speed of second car $=60mph$

As we know, Distance = Speed $\times$ Time

If the first car covered the distance $d$

Then the distance covered by second car will be $1320-d$

Now form two equation taking time as $t$ from the given information and equate them.

$d=50\times t$

And $1320-d=60 \times t$

On solving the above equation:

$1320-50t=60t\\t=1320/110\\t=12$

Hence, to cover 1320 miles they will need 12 hours of time.

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