Question

6. How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?

Answer 1

Answer:

60 W

Explanation:

The work done in lifting the object is given by:

$W=Fd$

where

F = 30.0 N is the weight of the object

d = 10.0 m is the displacement covered by the object

Using the formula,

$W=(30.0 N)(10.0 m)=300 J$

Now we can calculate the power, which is given by

$P=\frac{W}{t}$

where

W = 300 J is the work done

t = 5.00 s is the time interval

Substituting,

$P=\frac{300 J}{5 s}=60 W$