Question

One number is 4 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 538, find the numbers

Answer 1

Answer:

73

292

173

Step-by-step explanation:

x = first number

4x = second number

100 + x = third number

x + 4x + 100 + x = 538

6x + 100 = 538

6x + 100 - 100 = 538 - 100

6x = 438

6x/6 = 438/6

x = 73

Check:

73 + 4(73) + 100 + 73 = 538

73 + 292 + 173 = 538

538 = 538

Answer 2

Answer:

The numbers are 73, 173 and 292.

Step-by-step explanation:

If the numbers are x, y and z we have:

y = 4x

z = x + 100

x + y + z = 538

Substituting for y in the last equation:

x + 4x + z = 538

5x + z = 538.............(1)

From the second equation:

z - x = 100................(2)

Equation (1) - (2) gives:

6x = 438

x = 73

Therefore y = 4x) = 4(73) = 292

and z = x + 100 = 73 + 100 = 173.