Question

The average January surface water temperatures (°C) of Lake Michigan from 2000 to 2009 were 5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94, and 4.34. The data set has the following statistics:

x = 4.312
2 = 0.577
What is the standard deviation? Round to the nearest thousandth.

0.333
0.760
2.077
18.593

Answer 1

Answer: Second Option

$\sigma=0.760$

Step-by-step explanation:

We have the average January surface water temperatures (°C) of Lake Michigan from 2000 to 2009.

5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94, 4.34

We know that the average ${\displaystyle {\overline {x}}}$ of the data is:

${\displaystyle {\overline {x}}}=\frac{\sum_{i=1}^{10}x_i}{10}=4.312$

We also know that the variance $\sigma^2$ is equal to 0.577.

So by definition the standard deviation $\sigma$ is:

$\sigma=\sqrt{\sigma^2}\\\\\sigma=\sqrt{0.577}\\\\\sigma=0.760$

Answer 2

Answer:0.760

just right by chance