Answer:
value of t is greater than equal to -9 / 28.
Step-by-step explanation:
Given Quadratic Polynomial : tx² + 3x - 7 = 0
Also, It has real solutions.
Standard Quadratic equation, is ax² + bx + c = 0
here, Determinant, D = b² - 4ac
decides nature of the roots.
if D < 0 , roots / solutions are complex
if D = 0 , roots are real and equal.
if D > 0 , roots are real and different.
As given roots are real solutions.
Means Dis either equal to 0 or greater than 0
when D = 0
we have, 3² - 4 × t × (-7) = 0
9 + 28t = 0
t = -9 / 28
when D > 0
we have, 3² - 4 × t × (-7) > 0
9 + 28t > 0
t > -9 / 28
Therefore, value of t is greater than equal to -9 / 28.
