Respuesta :

[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ \cline{1-1} V=36\pi \end{cases}\implies 36\pi =\cfrac{4\pi r^3}{3}\implies 108\pi =4\pi r^3 \\\\\\ \cfrac{108\pi }{4\pi }=r^3\implies 27=r^3\implies \sqrt[3]{27}=r\implies \boxed{3=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a sphere}\\\\ SA=4\pi r^2\qquad \qquad \implies SA=4\pi \left( \boxed{3} \right)^2\implies SA=4\pi (9)\implies SA=36\pi[/tex]