Question

Graph the line with slope2/3 passing through the point(-2, 1)

Answer 1

Answer:

The graph in the attached figure

Step-by-step explanation:

step 1

Find the equation of the line into point slope form

The equation of the line is equal to

$y-y1=m(x-x1)$

substitute the given values

$y-1=(2/3)(x+2)$

step 2

To graph the line find the intercepts

Find the y-intercept

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

$y-1=(2/3)(0+2)$

$y=(4/3)+1$

$y=(7/3)$

The y-intercept is the point (0,7/3)

Find the x-intercept

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

$0-1=(2/3)(x+2)$

$-1=(2/3)x+(4/3)$

$(2/3)x=-(4/3)-1$

$(2/3)x=-(7/3)$

$2x=-7$

$x=-7/2$

The x-intercept is the point (-7/2,0)

step 3

Plot the intercepts to graph the line

see the attached figure