Question

What is the general form of the equation of the line shown?

Answer 1

Answer:

The desired equation is y = (-8/3)x + 3.

Step-by-step explanation:

There's no one general form; several different forms apply here.

Seeing that the y-intercept is (0, 3) and that another point on the line is (3, -5), I'd use the slope-intercept form here:  y = mx + b

As we move from the first point to the second, x increases by 3 and y decreases by 8.  Thus, the slope of the line through the two points is

m = rise / run = -8/3.  As before, the y-intercept is (0, 3), so b = 3.

The desired equation is y = (-8/3)x + 3.

Answer 2

Hello!

The answer is:

The first option:

$3x+y-3=0$

Why?

To find which is the equation of the line shown, we need to find  a line that intercepts the y-axis at 3 and the x-axis and 1.

So,  discarding we have:

First equation:

$3x+y-3=0$

Making "x" equal to 0 in order to find the y-axis intercept, we have:

$3(0)+y-3=0$

$y=3$

Making "y" equal to 0 in order to find the x-axis intercept, we have:

$3x+0-3=0$

$3x=3$

$x=\frac{3}{3}=1$

So, we have found that the x-axis and y-axis intercept of the equation, are the shown in the picture.

The interception points of the equation and the line are:

For x-axis:

$(1,0)$

For y-axis:

$(0,3)$

Hence, the answer is the first option.

$3x+y-3=0$

Have a nice day!