the radius of a cylinder is multiplied by 6 while the height is kept the same. what effect does this have in the volume of the cylinder​

Respuesta :

[tex]\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=\stackrel{\times 6}{6r} \end{cases}\implies V=\pi (6r)^2 h\implies V=\pi (6^2r^2) h \\\\\\ V=36~~\pi r^2 h\impliedby \textit{36 times the original volume}[/tex]

The effect that multiplying the radius by 6 would have on the volume of the cylinder is the volume would increase by a factor of 36

Calculating the volume of a cylinder

From the question, we are to determine what effect multiplying radius by 6 would have on the cylinder

Using the formula for calculating the volume of a cylinder

V = πr²h

Where V is the volume of the cylinder

r is the radius

and h is the height

If the r is the radius and h is the height of the first cylinder,

Then, volume of the first cylinder will be

V = πr²h

For the new cylinder

radius = 6r

and h = h

Then, volume of the new cylinder will be

V₂ = π × (6r)² × h

V₂ = π × 36r² × h

V₂ = 36πr²h

The new volume is multiplied by a factor of 36

Hence, the effect that multiplying the radius by 6 would have on the volume of the cylinder is the volume would increase by a factor of 36.

Learn more on Calculating the volume of a cylinder here: https://brainly.com/question/18757852

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