A farmer in china discovers a mammal hide that contains 70 of its original amount of c-14 N=noe^kt No=initial amount of c-14 at time t K=0.0001 T=time in years

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Answer:

N=N(sub o)e^-kt  

N/N(sub o)=e^-kt  

70/100=e^-kt  

ln .7=-.0001t  

t=ln .7/-.0001

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