Respuesta :
Answer:
a = 1500 (initial Bone density)
b = 0.97 (remaining percentage every year)
x = x (years)
Step-by-step explanation:
The question already sets x as the "years" variable, and the function must be expressed:
[tex]f(x) = a*b^x[/tex]
Then we can set a as the initial bone density: 1,500 kg/mg3
and b as the remaining percentage after each year: 100% - 3% = 97%
In decimal notation: 97% is equivalent to 0.97
The x exponent of b represents the succesive density reduction each year.
For example, replacing for values for the first 5 years we obtain the following results:
(Note: results are limited and rounded to two decimals)
[tex]f(x) = 1500*0.97^1 = 1455[/tex]
[tex]f(x) = 1500*0.97^2 = 1411.35[/tex]
[tex]f(x) = 1500*0.97^3 = 1369,01[/tex]
[tex]f(x) = 1500*0.97^4 = 1327,94[/tex]
[tex]f(x) = 1500*0.97^5 = 1288,10[/tex]