Respuesta :
Answer:Answer: All real numbers greater than -1. Step-by-step explanation: We have to find the range of: y= 2e^x-1. We know that e^x lies in (0,∞). Hence, 2e^x lies in (0,∞). Hence, 2e^x-1 lies in (-1 ...
Step-by-step explanation:Answer: All real numbers greater than -1. Step-by-step explanation: We have to find the range of: y= 2e^x-1. We know that e^x lies in (0,∞). Hence, 2e^x lies in (0,∞). Hence, 2e^x-1 lies in (-1 ...
Answer:
B. All real numbers greater than –1.
Step-by-step explanation:
We have been given a function [tex]y=2e^x-1[/tex]. We are asked to find the range of our given function.
We know that the range of an exponential function [tex]f(x)=c\cdot n^{ax+b}+k[/tex] is [tex]f(x)>k[/tex].
Upon looking at our given function, we can see that [tex]k=-1[/tex], therefore, the range of our given function would be [tex]y>-1[/tex] that is all real numbers greater than [tex]-1[/tex].
