Question

g(1)=2.7
g(n)=g(n-1)*6.1
find an explicit formula for g(n)

Answer 1

By substitution,

$g(2)=6.1g(1)$

$g(3)=6.1g(2)=6.1^2g(1)$

$g(4)=6.1g(3)=6.1^3g(1)$

and so on, so that

[tex]g(n)=6.1^{n-1}g(1)=2.7\cdot6.1^{n-1}

Answer 2

Answer:

2.7(6.1)^(n-1)

Step-by-step explanation:

[(6.1)^(n-1)]*g(1)

=[(6.1)^(n-1)]*2.7

=2.7*(6.1)^(n-1)