Question

This shouldn't be too difficult i just don't know what i'm doing please help

Write the expression below as a function of cos only.

sin²x/1+cos x

Answer 1

Answer:

$\frac{1-cos^2x}{1+cosx}$

Step-by-step explanation:

We are given the expression

$\frac{sin^2x}{1+cosx}$

We can use the Pythagorean identity of $sin^2x+cos^2x=1$ when solved for $sin^2x=1-cos^2x$

Now we can substitute in our identity for $sin^2x$

$\frac{1-cos^2x}{1+cosx}$